How to compute arccos for a matrix?
13 views (last 30 days)
Show older comments
I would like to compute the arccos for a matrix. I know when I want to find log(), exp(), and sqrt () for a matrix , we use logm(A), expm(A) and sqrtm(A) where A is a matrix.
I want to find the following:
x=acos(sqrtm(A)\eye(n))
so, Is it correct to compute it like this ? Or we need to use arccosm(sqrtm(A)\eye(n))? Thank you.
2 Comments
Walter Roberson
on 4 Jul 2020
There are no trig matrix functions in MATLAB, except the ones that work element by element.
Answers (1)
Walter Roberson
on 5 Jul 2020
It depends what you are trying to calculate.
And so we could potentially generalize that for matrices, there might be some meaning to
arccosm = @(z) 1i * logm(z + sqrtm(z^2 - 1))
I am having difficulty thinking of a context in which there could be physical meaning for this.
If we substitute in 1/sqrtm(A) then
1i*logm(sqrtm(A\eye(n) - 1) + sqrtm(A)\eye(m))
But is there a meaning for this??
11 Comments
Walter Roberson
on 7 Jul 2020
f1 = @(x) acos(sqrtm(x)^(-1)) * sqrtm(x)^(-1);
f2 = @(x) acos(sqrtm(x)/eye(size(x,1))) / sqrtm(x);
f3 = @(x) acos(1./sqrt(x)) ./ sqrt(x);
f1(A)
f2(A)
f3(A)
Try them all and decide which one is the right solution for you.
See Also
Categories
Find more on Matrix Indexing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!