how to produce interval from this matrix?

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Columns 1 through 6
0 0.1131 0.2134 0.3023 0.3812 0.4512
0 0.2134 0.3812 0.5132 0.6171 0.6988
0 0.3023 0.5132 0.6604 0.7631 0.8347
0 0.3812 0.6171 0.7631 0.8534 0.9093
0 0.4512 0.6988 0.8347 0.9093 0.9502
0 0.5132 0.7631 0.8847 0.9439 0.9727
0 0.5683 0.8136 0.9195 0.9653 0.9850
i want interval between column 2 and 1
column 3 and 2
column 4 and 3
column 5 and 4
column 6 and 5
and then i want
the result of those interval devided each other like:
interval column 3 and 2/ interval column 2 and 1
interval column 4 and 3/ interval column 3 and 2
interval column 5 and 4/ interval column 4 and 3
and soon
  2 Comments
per isakson
per isakson on 23 Nov 2012
Azzi, I guess "so on". However, what does OP mean by "interval"?
uncung fgv
uncung fgv on 24 Nov 2012
sorry my native not english. interval in my mind is determination or different-ial. like 6 and 4 the 'interval'= 2 (minus)

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Accepted Answer

Matt J
Matt J on 24 Nov 2012
Edited: Matt J on 24 Nov 2012
Here's a wild guess at what you mean
diff(A(:,2:end),1,2)./diff(A(:,1:end-1),1,2)
  4 Comments
Matt J
Matt J on 24 Nov 2012
Edited: Matt J on 24 Nov 2012
A little more efficiently, then
temp=diff(A,1,2);
out=temp(:,2:end)./temp(:,1:end-1);
uncung fgv
uncung fgv on 24 Nov 2012
many thanks. gratefull i know this site.

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