For loop using bin2dec conversion
1 view (last 30 days)
Show older comments
Darshan Manjunathrao Chawan
on 30 May 2020
Commented: Darshan Manjunathrao Chawan
on 30 May 2020
input=[1 1 0 1 0 0 1 0 ]; %input bit
x1=bin2dec(num2str(11)); %converting number to characters
x2=bin2dec(num2str(01));
x3=bin2dec(num2str(00));
x4=bin2dec(num2str(10));
xx=[x1,x2,x3,x4];
This is my code, I don't want to use individual bin2dec conversion. How can I put it in 'for loop'?
0 Comments
Accepted Answer
Stephen23
on 30 May 2020
Edited: Stephen23
on 30 May 2020
This is MATLAB, you don't need a for loop!
Method one: mtimes:
>> V = [1,1,0,1,0,0,1,0];
>> N = 2;
>> X = pow2(N-1:-1:0)*reshape(V,N,[])
X =
3 1 0 2
Method two: bin2dec:
>> V = [1,1,0,1,0,0,1,0];
>> N = 2;
>> X = bin2dec(reshape(sprintf('%u',V),N,[]).');
X =
3
1
0
2
3 Comments
Stephen23
on 30 May 2020
"But can't I put it in for loop to determine individual values"
Of course, you can use a loop if you want to. Try it.
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!