Info

This question is closed. Reopen it to edit or answer.

Avoiding for loop and if

2 views (last 30 days)
Giovanni Gardan
Giovanni Gardan on 19 May 2020
Closed: MATLAB Answer Bot on 20 Aug 2021
I'd like to avoid the following "for loop". Is it possible?
In the following code, the matrix CAR_GEN is the input. This matrix has rows number=1000, and column number=4. In the first column of this matrix there are two possibilities: or 'G' or 'C', and if I have 'C' i have to do the operation under the if-test and finally find the vector ''Scarto''.
Is it possible to check directly if the element of the first column is 'C' and then do the operation in order to find 'Scarto', in order to save time?
-----------------------------------------------------------------------------------------------------------------------------
Scarto = zeros (N_nodi_tot - N_nodi_gen,1); %Array initialization
for Riga = 1:100000
if CAR_GEN(Riga,1) == abs('C')
Ncar = CAR_GEN(Riga,2);
Pcar = CAR_GEN(Riga,3)/Nbase;
Qcar = CAR_GEN(Riga,4)/Nbase;
Nload = Ntot(Riga,1);
Scarto(Ncar,1) = Nload - (Pcar + 1i*Qcar);
end
end
---------------------------------------
----------------------------------------------------------------------------------------
Thanks!
  3 Comments
Giovanni Gardan
Giovanni Gardan on 19 May 2020
Thank you very much for your answer. Is this the right way to use logical indexing?
Scarto = zeros (N_nodi_tot - N_nodi_gen,1);
cond = (CAR_GEN(:,1) == abs('C'));
Ncar = CAR_GEN(cond,2);
Pcar = CAR_GEN(cond,3)/Nbase;
Qcar = CAR_GEN(cond,4)/Nbase;
Nload = Ntot(cond,1);
Scarto(Ncar,1) = Nload - (Pcar + 1i*Qcar);
Walter Roberson
Walter Roberson on 19 May 2020
Looks plausible.

Answers (0)

This question is closed.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!