Specifying a range in a double

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Keith Grey
Keith Grey on 15 May 2020
Commented: Keith Grey on 15 May 2020
% Values is a 401x1 double: 1 - 401
% In this example, I want to take the mean from Values(90) to Values(110).
% Specify Bounds
MAX = 90; %
MIN = 110;
idy = find(Values == MIN);
idz = find(Values == MAX);
Values = mean(Values(idy:idz));
This is simple & should be returning 1 number from Values after taking the mean, but it's resulting in a 1x7^6 double.
Is there a syntax error that I'm overlooking here?
  1 Comment
Fangjun Jiang
Fangjun Jiang on 15 May 2020
code is simple enough. run the code line by line and see where is wrong.
The numerical value for MAX and MIN seems to be reversed. Is that correct?

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Accepted Answer

William Alberg
William Alberg on 15 May 2020
I think, that you want to do this:
MAX = 110;
MIN = 90;
id = find( (MIN <= Values) & (Values <= MAX) )
Values = mean(Values(id))
I switched the MIN/MAX values
  1 Comment
Keith Grey
Keith Grey on 15 May 2020
Ah, I see what I did now! The MAX value was lower than the MIN, so of course the computer's going to hate that. Thank you very much!

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R2017b

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