Help with a loop

4 views (last 30 days)
Konstantina Vaitsi
Konstantina Vaitsi on 13 May 2020
I need to write a script where I have two matrixes. One S = [12 4 6 4;16 12 2 3;0 4 10 12;4 12 21 3] and one CLN = 50*ones(4). I need to create a loop where in every step all the cells in S matrix are decreased by 2 and a new CLN matrix is calculated depending on the S and the previous CLN. Specifically,
CLN(i,j) = CLN(i,j) -0.5*S(i,j) if S(i,j) <5,
CLN(i,j) = CLN(i,j)+ 0.5*S(i,j) if S(i,j) > =5
and CLN(i,j) = 0 if CLN(i,j)-0.5*S(i,j)<0.
This is what I have written so far but it doesn't work
S = [12 4 6 4;16 12 2 3;0 4 10 12;4 12 21 3];
CLN = 50*ones(4);
i = 1:4;
j = 1:4;
for t = 0:4
B = [S - 2*t];
B(B<0)=0
Y = zeros(size(B));
Y(B<5) = CLN - 0.5*B(B<5);
Y(B>=5) = CLN + 0.5*B(B>=5);
Y(CLN - 0.5*B<0) = 0(CLN - 0.5*B<0)
endfor

Accepted Answer

William Alberg
William Alberg on 15 May 2020
S = [12 4 6 4;16 12 2 3;0 4 10 12;4 12 21 3];
CLN = 50*ones(4);
for i = 1:4
S = S - 2;
CNL_new = CLN;
% If S is below 5
index = S < 5;
CNL_new(index) = CLN(index) - 0.5*S(index);
% If S is above or equal to 5
index = S >= 5;
CNL_new(index) = CLN(index) + 0.5*S(index);
% if CLN - 0.5*S < 0
index = (CLN - 0.5*S) < 0;
CNL_new(index) = 0;
CLN = CNL_new;
end
Does this help?
  1 Comment
Konstantina Vaitsi
Konstantina Vaitsi on 15 May 2020
I spent days on it not knowning what to do. I made a few adjustments and it finally works! Thanks a million :)

Sign in to comment.

More Answers (0)

Categories

Find more on Matrices and Arrays in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!