- Declare variables using syms.
- Build the expression.
- Define the first and second derivative using diff function.
symbolic derivative of lagrangian & kinematic coefficient
1 view (last 30 days)
Show older comments
Hi
II am working on some mechanical problems.
basically trying to take symbolic derivative of kinematic coefficients for the purpose of checking my hand calculations..
so here is the position scaler ; r2 cos(th2) - r3 * cos(th3) = 0
taking derivative with respect to th2 (theta2) , Vx = -r2 *sin(th2) + r3 *sin(th3) * d(th3)/d(th2) - cos(th3)*d(r3)/d(th2) = 0
and differentiate again for acceleration with respect to th2
Could you please explain on how this can be achieved using matlab?
0 Comments
Answers (1)
Guru Mohanty
on 11 May 2020
Hi, I understand you want to find the first and second derivative of the following expression. You can do this by the following steps.
Here is a sample code for it.
syms th2 r2 th3(th2) r3(th2)
disp = r2*cos(th2) - r3*cos(th3);
vel=diff(disp,th2);
accel=diff(vel,th2);
0 Comments
See Also
Categories
Find more on Symbolic Math Toolbox in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!