Problem with answer 15.2 Creating and Calling Functions: (4/6) Create and Call a Function, task 1 MATLAB Fundamentals

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The problem asks us to modify the function call using two inputs. I put the answer as follows:
top5 = getLargestN(x,5)
i get a message 'error using exercise>getLargestN too many input arguments'.
The answer i solution is identical to one I gave. How do I move forward here?

Accepted Answer

Geoff Hayes
Geoff Hayes on 5 May 2020
Gareth - did you update the function signature as well so that it accepts two inputs? Presumably you have defined the function (with body) like
function [res] = getLargestN(x)
and you would need to change this to
function [res] = getLargestN(x,y)
% do something in code with y
so that the signature matches how you are calling it (when you pass in the x and 5).
  3 Comments
Geoff Hayes
Geoff Hayes on 5 May 2020
Gareth - I would first try to get the function returning the correct response (I don't understand either what "check that x is not modified" means). So right now your function is
function Y= getLargestN(x,5)
top5=Y
end
There are a couple of problems. The signature defines the output parameter and the input parameters. These parameters are variables and since 5 is not a variable (but a value) you cannot define it as a parameter. (You can pass 5 into this function when you call it.) So change this to something like
function Y = getLargestN(x, numElements)
Try to name the variables as to their purpose. Next, the output parameter is Y but is not set anywhere in your code. In fact, you are trying to use it before it has been defined. (I think the top5 variable is meant to be the output from this function when you call it...and not a variable within the function because you don't know how many elements you will be asked to extract.
function Y = getLargestN(x, numElements)
Y = ...;
end
Now you just have to sort the data.
Gareth George
Gareth George on 6 May 2020
Thanks Geoff! I got there in the end. Really helpful. I've been used to doing these tasks one at a time, so didn't anticipate having to edit code in a window further down first :)

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More Answers (3)

Sanket
Sanket on 4 Nov 2022
y0 = 0.4;
yline(y0)
tzerox = findcrossing(t,x-y0)
tzeroy = findcrossing(t,y-y0)

Bhavesh  Pawar
Bhavesh Pawar on 11 Mar 2022
y0 = 0.4;
yline(y0)
tzerox = findcrossing(t,x,y0)
tzeroy = findcrossing(t,y,y0)
  5 Comments

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Joed Blair Jacalan
Joed Blair Jacalan on 12 Aug 2023
  1. Modify the definition of the findcrossing function so that it takes a third input z.
  2. Add a new line to the beginning of the function:y = y - z;
  3. In the Task 1 section of the script, change the value of y0 to 0.4.
  4. Modify the two calls to findcrossing to add y0 as an input.
You can use the graph to check that the returned values of t are correct (x(t) = 0.4 and y(t) = 0.4)

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