Phasor representation of complex numbers
100 views (last 30 days)
Show older comments
Aleem Andrew
on 20 Apr 2020
Commented: Star Strider
on 25 Jun 2022
Instead of typing (3+4i)*(i), how can I multiply two complex numbers in phasor form, in this case
(5∠(arctan(4/3))*(∠90), and convert the result to rectangular form? I have tried representing the complex numbers as [r theta], but typing [5 arctan(4/3)]*[1 90] does not give the correct answer.
0 Comments
Accepted Answer
Star Strider
on 20 Apr 2020
Converting to phasor representation is definitely taking the long way round.
If you must:
r2p = @(x) [abs(x) rad2deg(angle(x))]; % Rectangular -> Phasor
p2r = @(x) x(1)*exp(1i*deg2rad(x(2))); % Phasor -> Rectangular
pm = @(x,y) [x(1)*y(1) x(2)+y(2)]; % Phasor Multiply
pd = @(x,y) [x(1)/y(1) x(2)-y(2)]; % Phasor Divide
x = 3+4i;
xp = r2p(x);
yp = [1 90];
xptimesyp = pm(xp,yp)
xrtimesyr = p2r(xptimesyp)
Check = x * p2r(yp)
producing:
xptimesyp =
5 143.13
xrtimesyr =
-4 + 3i
Check =
-4 + 3i
.
2 Comments
More Answers (1)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!