Whats wrong with my code? Taylor series Approx with error
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When I take out the error if statement, the code works just fine and displays all iterations. However, with the error statement in (line 7 of code) the m file runs but will not display any answers.
x = 0.9;
true = sin(x);
s = 0; %initialize sum
for n = 0:20
f = (((-1)^n)*x^((2*n)+1))/(factorial((2*n)+1)); %McLauren Series for sin function
s = s+f; %sum the start with the series
error = ((true-s)/true)*100; %Percent Error Formula
if error < 0.0001 ,break;end
fprintf('%f\t %f\t %f\t\n',true,s,error);
end
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Answers (1)
James Tursa
on 1 Apr 2020
You probably just need an absolute value
error = abs((true-s)/true)*100; %Percent Error Formula
That being said, true and error are names of existing MATLAB functions. You should probably pick different names such as true_value and err.
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