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I am asking for help in plotting a line graph in my "for" loop program. The program is able to run the calculations but I am not able to graph. Below is the code i have created.

clc

f=196.2;

fi=0; finc= pi/180; ff=pi/4

for x=0:pi/180:pi/4;

ac= (f*cos(x))/((sin(pi/6)*cos(x))+(cos(pi/6)*sin(x)))

fprintf('Force of AC is %7.2f\n',ac)

bc= ((ac*cos(pi/6))/cos(x))

fprintf('Force of BC is %7.2f\n',bc)

end

hold on;

xx=x(1:length(x));

plot(xx,ac)

KSSV
on 24 Mar 2020

YOu need not use a loop as the other user has suggested you. If you use a loop, you need to intiilaize the array and save it in a loop as below:

f=196.2;

fi=0; finc= pi/180; ff=pi/4 ;

x=0:pi/180:pi/4;

ac = zeros(size(x)) ;

for i = 1:length(x)

ac(i)= (f*cos(x(i)))/((sin(pi/6)*cos(x(i)))+(cos(pi/6)*sin(x(i))))

fprintf('Force of AC is %7.2f\n',ac)

bc= ((ac*cos(pi/6))/cos(x(i)))

fprintf('Force of BC is %7.2f\n',bc)

end

plot(x,ac)

Sriram Tadavarty
on 24 Mar 2020

Hi Jose,

This code need not require a for loop. The following can be done to get the same result:

clc

f=196.2;

fi=0; finc= pi/180; ff=pi/4

x=0:pi/180:pi/4;

ac= (f*cos(x))./((sin(pi/6)*cos(x))+(cos(pi/6)*sin(x)))

fprintf('Force of AC is %7.2f\n',ac)

bc= ((ac*cos(pi/6))./cos(x))

fprintf('Force of BC is %7.2f\n',bc)

hold on;

plot(x,ac)

Hope this helps.

Regards,

Sriram

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