Data extraction of dates
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I have a column of data with rainfall on each day, from 2004 to 2016. I want to be able to extract the rainfall data for each day and store that data into columns of months for each year. I have created a loop that finds the end day of all months from 2004 to 2016, but am having trouble now extracting the information.
[SL: formatted question as text not code]
2 Comments
Mohammad Sami
on 24 Mar 2020
Edited: Mohammad Sami
on 24 Mar 2020
Create a vector to store the index of the days (rows) you want to extract. Then you can simply subset.
Asanka Subasinghe
on 24 Mar 2020
Answers (1)
Walter Roberson
on 24 Mar 2020
Edited: Walter Roberson
on 24 Mar 2020
Dv = Dates(:) ;
Output = accumarray([day(Dv), month(Dv), year(Dv)-2003], Rainfall(:), [31 12 13], [], nan);
The result will be a 3d array with one pane for each year, with rows being day numbers, columns being month numbers. Unused entries such as shorter months or missing data will be set to nan
6 Comments
Asanka Subasinghe
on 25 Mar 2020
Asanka Subasinghe
on 25 Mar 2020
Walter Roberson
on 25 Mar 2020
Use readtable so that you get datetime objects not date vectors.
Asanka Subasinghe
on 25 Mar 2020
Asanka Subasinghe
on 25 Mar 2020
Walter Roberson
on 25 Mar 2020
clc;clear all;close all
filename='Data Q2 (2).xlsx';
data=(readtable(filename))
dandenongnum=data{:,2};
dandenongdate=data{:,1};
Dv=dandenongdate;
Output = accumarray([day(Dv), month(Dv), year(Dv)-2003], dandenongnum, [31 12 13], [], nan);
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