unknown code- understand it up to the for loop but am lost from there. Can anyone lend a hand? thanks.
1 view (last 30 days)
Show older comments
Josh Williams
on 15 Mar 2020
Edited: Image Analyst
on 15 Mar 2020
dat=load('data.dat')
a=dat(:,1)
b=dat(:,2)
s=size(a)
s=s(1)
out=zeros(s,1)
for n=1:s
out(n)=(b(n+1)-b(n-1))/(a(n+1)-a(n-1))
end
c=[a out]
0 Comments
Accepted Answer
Thiago Henrique Gomes Lobato
on 15 Mar 2020
What the code was supposed to be? it looks like the variable out is suppose to be the numerical derivative of b with respect to a. If the distance between each "a" is uniform and increasing, than this is the central scheme for 1st order differentiation with 2nd order accuracy and the line describe basically .
2 Comments
Thiago Henrique Gomes Lobato
on 15 Mar 2020
Size returns two values, so s(1) saves the first dimension in order to perform the loop and size assignment. It would be the same if you did:
s=size(a,1);
out=zeros(s,1);
...
More Answers (0)
See Also
Categories
Find more on Creating and Concatenating Matrices in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!