Vector Input, GUI edit text box

Hi,
I am trying to get a vector input from the user in a GUI using edit text boxe, but it seems that the program doesn't recognize the text boxes, although I have them in my GUI. Can someone tell what is the problem?
% --- Executes on button press in pushbutton1.
function pushbutton1_Callback(hObject, eventdata, handles)
% hObject handle to pushbutton1 (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)
Xn=str2num(get(handle.edit1,'string'));
Yn=str2num(get(handle.edit2,'string'));
dn=str2num(get(handle.edit3,'String'));
The class handle has no Constant property or Static method named 'edit1'.

12 Comments

Hi Daniel,
Replace the variable 'handle' with 'handles' while calculating Xn, Yn and Dn. This should solve.
Regards,
Sriram
Thank You,
Now Im having another problem.
I used asingin function to see what is the input I get for Xn, Yn, Dn.
My inputs are: for Xn-0,1.5,0,5,6.5,10 , for Yn-0,0,1.5,4,4,6 , for dn-1,1,1,1,1,1, but what I get is:
% --- Executes on button press in pushbutton1.
function pushbutton1_Callback(hObject, eventdata, handles)
% hObject handle to pushbutton1 (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)
Xn=str2double(get(handles.edit1,'String'));
assignin('base','Xn',Xn);
Yn=str2double(get(handles.edit2,'String'));
assignin('base','Yn',Yn);
dn=str2double(get(handles.edit3,'String'));
assignin('base','dn',dn);
Daniel - is there a reason that you are assigning these varaibles to the base workspace? Why not just add them as fields to the handles structure so that other callbacks in your app can access them?
Also, try using str2num instead of str2double since the former should preserve the array:
>> x = '-0,1.5,0,5,6.5,10';
>> str2num(x)
ans =
0 1.5000 0 5.0000 6.5000 10.0000
>> str2double(x)
ans =
NaN
Another way to convert the values without using str2num (which uses eval and can lead to undexpected behaviors) is,
x = '-0,1.5,0,5,6.5,10';
d = str2double(strsplit(x, ','))
or, depending on how the values are delimited,
x = '-0 1.5 0 5 6.5 10';
d = str2double(strsplit(x))
Geoff Hayes, I tryed using str2num and it returns me the following error: "Error using str2num (line 31)
Requires character vector or array input."
Adam Danz, the input is something the user should type to the edit texts in the GUI, not directly to the code.
"the input is something the user should type to the edit texts in the GUI, not directly to the code."
Yeah, I'm aware of that. The x values in my comment were for demonstration purposes. They should be similar to the values you get from
x = handle.edit1.string;
% or
x = get(handle.edit1,'string')
If you get an error, we'll need to see what the input looks like.
Note that this method allows the user to enter anything including typos, brackets, and other symbols that won't be interpretted correctly. You could use a try/catch to prompt the user to try again if they didn't enter a proper input.
Now I'm getting the following error:
"Error using strsplit (line 80)
First input must be either a character vector or a string scalar."
Adam Danz
Adam Danz on 18 Mar 2020
Edited: Adam Danz on 18 Mar 2020
Please show us the input.
thit is how the input looks like
No brackets, just commas

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 Accepted Answer

Adam Danz
Adam Danz on 18 Mar 2020
Edited: Adam Danz on 18 Mar 2020
The string from a edit box is returned as a cell array of characters. If the expected inputs are a comma separated vector such as "1, 2, 3.14, 5", here's how to exact those values.
s = handles.edit1.String;
d = str2double(strsplit(s{:}, ','));
I suggest using conditional error detection in order to provide the user with feedback in case they use an incompatible format.
s = handles.edit1.String;
try
d = str2double(strsplit(s{:}, ','));
catch
error('Edit field must contain comma separated values such as "6, 5, 3.14"')
end

2 Comments

Thank you, It works :)
The string value extracted from the edit box is actually a cell array of characters. So, if the user enters "1,1,2,4" the string output will be {'1,1,2,4'}. The {:} part of my answer solves that by returning the character array within the cell array.

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