Numeric matrix to string matrix

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Hi,
Newbie here, need some assistance in solving this problem.
Input is a numeric matrix x (any dimension). Return value is a string matrix.
The rules are :
If the x <= 30, then return “small”, if 30 < x <= 50, then return “medium”, otherwise return “high”
When I run the first "If" statement by itself I get x = "low" "low" "low" "low"
Then when I add the elseif statement I get nothing. Matlab simply ouputs the same results.
It seems like the code is only looking at the first row of my matrix. It also seems that it's considering 45 as less than 30.
I appreciate all the help in advance. I'm new learner, slowly learning programming.
First if statement only.
A = [1 2 45 4 ; 5 6 45 8];
for i = 1:length(A);
if A(i) <= 30
x(i)= "low"
end
end
>>
x =
1×4 string array
"low" "low" "low" "low"
elseif statement
A = [1 2 45 4 ; 5 6 45 8];
for i = 1:length(A);
if A(i) <= 30
x(i)= "low"
elseif 30 > A(i) & A(i)<= 50
x(i) = "medium"
end
end
>>
x =
1×4 string array
"low" "low" "low" "low"

Accepted Answer

Ameer Hamza
Ameer Hamza on 7 Mar 2020
Edited: Ameer Hamza on 7 Mar 2020
x = [5 15 25;
35 45 55;
65 75 85];
result = strings(size(x));
result(x<=30) = "small";
result(x>30 & x<=50) = "medium";
result(x>50) = "large";
The result is
result =
3×3 string array
"small" "small" "small"
"medium" "medium" "large"
"large" "large" "large"
  1 Comment
Emmanuel Matata Bili Bili
Emmanuel Matata Bili Bili on 28 Mar 2020
Hi - Ameer,
Thank you for your answer. I completely forgot to say thanks.
I appreciate the help. Thanks!!!!

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More Answers (1)

Guillaume
Guillaume on 7 Mar 2020
The easiest way, by far, to do this in matlab is:
A = [1 2 45 4 ; 5 6 45 8]; %demo data
result = discretize(A, [-Inf, 30, 50, Inf], ["low", "medium", "high"])
  1 Comment
Emmanuel Matata Bili Bili
Emmanuel Matata Bili Bili on 28 Mar 2020
Allo Guillaume,
Thanks for the answer!
I completely got sidetracked and excited about trying both solutions and I forgot to say thanks.
It all worked fine with your solution as well.
Thank you!!

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