Replace missing value of cell array with NaN

please find attached file, I tried to replace missing values (-1.27605887595352e+39) with NaN, unfortunately I encountering with the following error. Thanks in advance any help.
INDEX = cellfun(@(x) (x<-1),presglb,'UniformOutput',false) ;
>> presglb_new = presglb(INDEX);
Function 'subsindex' is not defined for values of class 'cell'.

 Accepted Answer

Bhaskar R
Bhaskar R on 11 Feb 2020
Edited: Bhaskar R on 11 Feb 2020
ind = cellfun(@(x) (x<-1),presglb,'UniformOutput',false);
for ii =1 :length(presglb)
presglb{ii}(ind{ii}) = nan;
end

7 Comments

"ind" is corresponding to what?
is corresponding to the element below?
ind = cellfun(@(x) (x<-1),presglb,'UniformOutput',false) ;
Forgot to mention, now post is edited.
You are welcom :-)
Dear Bhaskar, after getting new presglb, you know how can I remove NaN?
Thanks
I know the following way, but the double size in the cell has changed, I want to keep the size as before.
>> result = cellfun(@(x) x(~isnan(x)), presglb, 'Uniform', 0);

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