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filtering problem, need help

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Dear
I have a EMG signal of 30000x4. with sampling frequency of 10KHz.
I filter noise by below code
NotchFilter = bandstop(Data01Raw,[49.9 50.1],Fs);
sEmgFilter = bandpass(NotchFilter(:,1:2),[20 500],Fs);
iEmgFilter = bandpass(NotchFilter(:,3:4),[600 2000],Fs);
Data02Filtered = [sEmgFilter iEmgFilter];
Questions
in above code bandpass or bandstop occur by which filer like is it butterwork or cheby or ellip?
I need to fiter the signal using butterworth 2nd order. How can i do this?
Thank you

  2 Comments

Walter Roberson
Walter Roberson on 1 Feb 2020
bandpass uses a fir filter if it can achieve the desgign goals with one, and otherwise uses a iir filter.

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Accepted Answer

Star Strider
Star Strider on 1 Feb 2020
Request two outputs from the bandpass and bandstop functions. The second output is the digital filter object. Displaying the digital filter object in your Command Window will tell you everything you need to know about it.
For example —
Fs = 10E+3;
[NotchFilter, df] = bandstop(Data01Raw,[49.9 50.1],Fs);
then:
df
displays:
df =
digitalFilter with properties:
Coefficients: [8×6 double]
Specifications:
FrequencyResponse: 'bandstop'
ImpulseResponse: 'iir'
SampleRate: 10.0000e+003
StopbandAttenuation: 60.0000e+000
PassbandRipple2: 100.0000e-003
StopbandFrequency2: 50.0843e+000
PassbandRipple1: 100.0000e-003
PassbandFrequency2: 50.1000e+000
PassbandFrequency1: 49.9000e+000
StopbandFrequency1: 49.9157e+000
DesignMethod: 'ellip'
Use fvtool to visualize filter
Use designfilt to edit filter
Use filter to filter data

  12 Comments

Show 9 older comments
Star Strider
Star Strider on 8 Feb 2020
It gives one value for each column of the matrix. That is what it is defined to do.
Ali Asghar
Ali Asghar on 8 Feb 2020
Dear, Can I find mutiple values of mav with this function?
Star Strider
Star Strider on 8 Feb 2020
I am not certain what you are asking. You can have buffer break the signal up into shorter segments if you want.
With respect to calculating the RMS value, if you have R2016a or later, you can use the movmean function instead of mean.
This computes the RMS value over a sliding window of 200 samples:
RMS_sigseg = sqrt(movmean(sigseg.^2, 200));
It results in a matrix the same size as the original matrix.
Note that the code you posted gives the mean of the absolute value. This is not the same as RMS value.

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