loop to work with the column

Hello! There is a loop, I need to know automatically how many values ​​after the point

X=[1 2 3 4 5 6 90 70 60 50 6 5 4 3 2
    1 2 3 4 5 6 60 70 60 50 6 5 4 3 2
    1 2 3 4 5 6 60 60 70 50 6 5 4 3 2]';
for i=1:length(X(1,:))
    [~,loc1]=max(X);
end
% and now I need to find out how many values ​​from maxim to 6
% ans(1) = 4 % 70 60 50 6 % ans(2)=3 % 60 50 6 % ans(3)=2

how do i do this?

[Stephen23]

"how many values ​​after the point"

What exactly is "the point" ?

What is that loop supposed to do?

[Lev Mihailov]

point of my maximum, the values should be from it to 6 (or close to this value 5.9.6.1)

p.s.the loop should get the same answers as mine

X=[1 2 3 4 5 6 90 70 60 50 6 5 4 3 2
    1 2 3 4 5 6 60 70 60 50 6 5 4 3 2
    1 2 3 4 5 6 60 60 70 50 6 5 4 3 2]';
% ans(1)=4; ans(2)=3; ans(3)=2

Answer 1

[KSSV]

iwant = sum(X>6,1) 

[Lev Mihailov]

iwant =

     4     4     4

such a variation gives the wrong answer