anonymous function and plotting
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Jackson vanHerwynen
on 26 Jan 2020
Answered: Star Strider
on 26 Jan 2020
In MATLAB, define this equation using an anonymous function, for example y(ω, x, E, I, `) = ... Then use values of ω = 2.0 kN/m, ` = 2 m, E = 70 GPa, and I = 0.00012 m4 to compute the deflection over the length of the beam. Create a plot of the deflection. Run the x-axis from 0 to 2 m and the y-axis from -0.01 to 0.01 m.
I wrote this but im confused.
y = @(w,x,E,I,l)((w*(x.^2))/(24*E*I).*((x.^2)+6*(l^2)-4*x*l));
y(2,0:.001:2,70,0.00012,2)
Im having trouble ploting this.
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Accepted Answer
Star Strider
on 26 Jan 2020
You are essentially where you want to be. It helps to assign the output of your function to a different variable. (I use ‘v’ here.)
I am not certain what problems you are having with the plot call. There are two ways to plot it:
y = @(w,x,E,I,l)((w*(x.^2))/(24*E*I).*((x.^2)+6*(l^2)-4*x*l));
v = y(2,0:0.001:2,70,0.00012,2);
figure
plot(v) % Plot As A Function Of The Vector Indices
grid
figure
plot((0:0.001:2), v) % Plot As A Function Of The Vector
grid
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