How to remove a value from matrix with same values in different positon?

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Pandiyaraj Gnanasekar on 7 Dec 2019
Answered: Roshni Garnayak on 13 Dec 2019
Hi everyone. I have 3x3 matrix of
T = [7,8,8 ; 6,4,10 ; 12,8,7]
I want to remove seven at first row and first column and not the other 7 in the last row and last column. How to remove it and same will apply for 8 also. I used indexing as T(T==7) = NaN; but it removes both values as the condition implies. Kindly please help with this. Thanks in advance.
Pandiyaraj Gnanasekar on 7 Dec 2019
I am extreamly sorry for the incovinience I'll attach the actual problem in this comment.
Mc = [1,3,2; 2,1,3; 1,2,3]; % Machine Number
PT = [7,8,10; 6,4,12; 8,8,7]; % Processing Time
Stime = zeros(3,3); %Start time
Etime = zeros(3,3); %End Time
T = zeros(3,3); %Temporary Matrix
for i = 1:3
for j = 1:3
machineIndex = Mc(i,j);
minV = min(PT(Mc==i));
Stime(i,j) = T(i,j);
for k = 1:n
if Stime(i,j) + minV >= T(i,k)
T(i,k) = Stime(i,j) + minV;
end
end
for k = 1:m
if Stime(i,j) + minV >= T(k,machineIndex)
T(k,machineIndex) = Stime(i,j) + minV;
end
end
Etime(i,j) = Stime(i,j)+ minV;
PT(PT==minV) = NaN;
end
end
I just want to schedule the minimum job first and next minimum job according to Machine Number. The processing time of Jobs are given in PT. I think this explains. And sorry for not explaining clearly.
dpb on 7 Dec 2019
Edited: dpb on 7 Dec 2019
What are n, m in the two loop limit expressions intended to be? They're undefined here.
"...schedule the minimum job first and next minimum job ..."
Why isn't the order just sort(minV) then?
T=sort(minV);
After that, ETime and STime will just be
Etime=cumsum(T);
Stime=[0;Etime(1:2)];
it would seem.

Roshni Garnayak on 13 Dec 2019
You can obtain the indices of the first occurrence of each value in a matrix using the ‘unique’ function. Refer to the following link for details on how to use ‘unique’:
After you obtain the indices you can find the indices which have duplicate values by using the ‘ismember’ function. Refer to the link below:
Refer to the code below to obtain your functionality:
T = [7,8,8 ; 6,4,10 ; 12,8,7];
[C, ia] = unique(T, 'first');
x = 1:numel(T);
[lic, lob] = ismember(x, ia);
T(x(~lic)) = NaN;

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