Wrong answer for sine function
1 view (last 30 days)
Show older comments
Ellen Brown
on 17 Nov 2019
Commented: Star Strider
on 17 Nov 2019
I am trying to create a function to evaluate sine at different values of t
function F = rforce(t)
F = 0.3 + 0.2.*sin(2.*pi.*t/365 - pi/2);
end
but this gives the incorrect answer when ran in matlab
2 Comments
Star Strider
on 17 Nov 2019
It would appear that the units of ‘t’ are days, so ‘F’ would be with respect to years (or fractions of years).
What result do you want?
Accepted Answer
Star Strider
on 17 Nov 2019
Define ‘t’ in terms of days (or fractions of days).
Try this:
rforce = @(t) 0.3 + 0.2.*sin(2.*pi.*t/365 - pi/2);
tdays = 1:0.25:365.25; % One Year in 6-Hour Increments
figure
plot(tdays, rforce(tdays))
grid
xlabel('Days')
ylabel('r Force')
xlim([min(tdays) max(tdays)])
2 Comments
More Answers (0)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!