matrix comparison and substitute value

1 view (last 30 days)
Nafila Farheen
Nafila Farheen on 6 Nov 2019
Answered: Walter Roberson on 6 Nov 2019
Hi, I have one matrix
A=[4 2 3
9 5 6]
I have another vector b=[1 0]. I want to compare the first column of A with b, and if the position in A correspondes to a 1 in b, then I would like to replace that value (4 multiply 0.99) and if 0, it will keep as it is . I was wondering is there any way to do that without executing nested for loops?TIA

Sign in to answer this question.

Answers (1)

Walter Roberson
Walter Roberson on 6 Nov 2019
A = A * (1 - 0.01 * (repmat(b.', 1, size(A,2)) == 1))

Categories

Find more on Data Types in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!