using relational operators on array and element

Hy,

I'm trying to figure out a way to sort my experiment data. I have a list with values which I want to look at but first I need to delte the ones that don't fit my criteria. For this case I developed the following code:

%tolerance
x=1
%values
T1=5:-5:-15;
%values2
T2=30:5:55;
%values3
f=30:5:120;
%dimension
d=size(meassure);
d=d(1);
%applying tolerance to values I want to extract
var1=T1-x;
var2=T1+x;
%loop to check for criteria
for i=1:d
   if T(i,6)>=var1 & T(i,6)<=var2;
    else T(i,6)=NaN;

My problem now is, because var1 and var2 are arrays it puts NaN to every value. Even though one of the values fits the if.... criteria.

I hope someone can help me and I explained my problem well enough

[Stephen23]

This looks like you are trying to write Python code:

for i=1:d
   if T(i,6)>=var1 & T(i,6)<=var2;
      else T(i,6)=NaN;

If you want to use MATLAB, then you will need to learn MATLAB code syntax.

[David Weise]

I know the basics of C and just learned some stuff about Matlab but not Python.

[Stephen23]

MATLAB is not very much like C.

The best way to learn basic MATLAB concepts is by working through the introdutory tutorials:

https://www.mathworks.com/help/matlab/getting-started-with-matlab.html

https://matlabacademy.mathworks.com/

Answer 1

[Daniel M]

if y>=var1 & y<=var2;

var1 = 4 -1 -6 -11 -16

var2 = 6 1 -4 -9 -14

Let's say y = 5, so the condition above will evaluate to

    ans =

  1×5 logical array

   1   0   0   0   0

How do you want the if statement to handle a logical array?

Perhaps you want to look into one of the following functions

   all()
   any()

[David Weise]

Thanks for your answer. I tried this now but not getting the right answers.

for i=1:d
    y=T(i,6)
    if y>=var1 & y<=var2
        if any(y==1)
    else T(i,6)=NaN
        end
    end
end

The code is running but doesn't change anything

[Daniel M]

I'm not sure you understand how if statements work. You should read up on that.