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gsourop
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I am not getting the correct answer when using datetime function

Asked by gsourop
on 17 Sep 2019 at 13:57
Latest activity Commented on by Guillaume
on 17 Sep 2019 at 14:38
Accepted Answer by dpb
Hi everyone,
I am using the following function
datetime(1,43100,1)
but instead of getting '31/12/2017' as an answer (as given from Excel), I am getting 01-Aug-3592. Apparently, I am missing something in the datetime function but don't know what it is.
Thanks in advance for your time.

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2 Answers

Answer by dpb
on 17 Sep 2019 at 14:07
 Accepted Answer

>> datetime(43100,'ConvertFrom','excel')
ans =
datetime
31-Dec-2017 00:00:00
>>
You tried converting from (yr,mo,day) --> (1, 43100, 1) instead.

  2 Comments

Thank you very much for the answer! How can I ignore the time part. I want to end up just with '31-Dec-2017' instead of '31-Dec-2017 00:00:00' .
The time part is always part of a datetime (hence the time in the name). You can avoid displaying it by changing the Format property:
>> datetime(43100,'ConvertFrom','excel', 'Format', 'dd-MM-yyyy')
ans =
datetime
31-12-2017
>> datetime(43100,'ConvertFrom','excel', 'Format', 'eee dd MMM yyyy')
ans =
datetime
Sun 31 Dec 2017
but note that the time part will still be taken into account for calculations (like date difference) whether or not it is displayed. Excel does the same.

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Answer by Ted Shultz
on 17 Sep 2019 at 14:05
Edited by Ted Shultz
on 17 Sep 2019 at 14:06

You are using
t = datetime(Y,M,D)
Year = 1
month = 43100
day = 1
That is not what you intend I assume.
I think you want:
t = datetime(43100,'ConvertFrom','excel')

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