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Divide an array in n different arrays

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luca
luca on 17 Sep 2019
Edited: Bruno Luong on 17 Sep 2019
Hi, given the array
V = [1 1 1 1 1 1 6 6 6 6 6 6 6 6 6 3 3 3 3 3 3 3 5 5 5 5 5 5 5 8 8 8 8 8 8 8 8 8 9 9 9 9 9 9 9 9 9 4 4 4 4 4 4 4 4 4 4 2 2 2 2 2 1 1 1 1 1 6 6 6 6 6 6 6]
and the matrix
A = [1 3 4
6 5 2
0 8 0
0 9 0]
I want to obtain 5 different arrays
a = [1 1 1 1 1 1 6 6 6 6 6 6 6 6 6];
b = [ 3 3 3 3 3 3 3 5 5 5 5 5 5 5 8 8 8 8 8 8 8 8 8 9 9 9 9 9 9 9 9 9];
c = [4 4 4 4 4 4 4 4 4 4 2 2 2 2 2 ];
d = [1 1 1 1 1 6 6 6 6 6 6 6];
so every time I meet the elements of one of the columns: 1-6 , 3-5-8-9 or 4-2 , I have to collect them and reported in a new array.
N.B zeros are never present in V, but are just inserted in A to create a square matrix
May someone help me with this task?

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Accepted Answer

Bruno Luong
Bruno Luong on 17 Sep 2019
Edited: Bruno Luong on 17 Sep 2019
V = [1 1 1 1 1 1 6 6 6 6 6 6 6 6 6 3 3 3 3 3 3 3 5 5 5 5 5 5 5 8 8 8 8 8 8 8 8 8 9 9 9 9 9 9 9 9 9 4 4 4 4 4 4 4 4 4 4 2 2 2 2 2 1 1 1 1 1 6 6 6 6 6 6 6]
A = [1 3 4
6 5 2
0 8 0
0 9 0]
[~,c,a] = find(A);
[~,i] = ismember(V,a);
g = c(i);
d = find([true; diff(g); true]);
c = mat2cell(V,1,diff(d));
c{:}

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