Time in hr min sec to seconds

I have a struct where the time field is written in hr min sec format with no dividers. For example, 152605 is 15:26 and 5 seconds. I’m trying to convert it to overall seconds but when I use datevec it gives me weird values, where the first row is equal to [417 10 25 0 0 0]. Is there a specific function for this? Can I pull out the number of hrs and mins to convert to seconds and add to the number of seconds in the time column?

I need to be able to do this by referencing the position in the struct, as there are 171 time stamps (I cannot input the time stamp manually). Desired outputs would be: different fields added to the struct that represent hours, mins, sec; one field added to the struct that represents the number of seconds equal to the time in hours, mins, seconds

The field in the struct that contains this data is data.time

[KALYAN ACHARJYA]

Input:

152605

Expected output?

Answer 1

[Stephen23]

>> str = '152605';
>> vec = sscanf(str,'%2d');
>> out = [60*60,60,1]*vec
out =  55565

[Bruno Luong]

alternative last statement

out = polyval(vec,60)

[Stephen23]

@Bruno Luong: I guess I am a bit old-fashoined, but I do like how this code uses only very basic and efficient operations.

[Bruno Luong]

No preference really, your method is clear and readable.

I just want to point out time counting is nothing but base-60 numbers.

Answer 2

[Bruno Luong]

round((datenum('152605','HHMMSS')-datenum('000000','HHMMSS'))*86400)

Answer 3

[Bruno Luong]

polyval(str2num(reshape('152605',2,3)'),60)

Answer 4

[Bruno Luong]

Purely arithmetics

x=str2double('152605');
h=floor(x/1e4);
y=mod(x,1e4);
m=floor(y/1e2);
s=mod(y,1e2); 
nsec=polyval([h,m,s],60)