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Extending an order in a vector

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Josué Ortega
Josué Ortega on 26 Aug 2019
Commented: James Tursa on 28 Aug 2019
I have a vector that provides me with a strict order of n number. If n is 5, for example, I type
y=randperm(5)
and I get something like
1 3 5 4 2
I want to scale this order by a factor of x. If x=3, I would like to get
1 2 3 7 8 9 13 14 15 10 11 12 4 5 6
Is there an easy way to do this that I am missing? I know that
reshape(repmat(y,x=3,1),1,[])
creates
1 1 1 3 3 3 5 5 5 4 4 4 2 2 2
and then I can add 1 to 3 using a loop, but surely there is something faster that I am missing.

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Josué Ortega
Josué Ortega on 28 Aug 2019
I have another question. The command you suggested gives me
1 2 3 7 8 9 13 14 15 10 11 12 4 5 6
is there a way to get the order of each group randomly?
So that I could get
3 1 2 9 7 8 13 14 15 11 10 12 4 6 5
Any ideas are most welcomed.
James Tursa
James Tursa on 28 Aug 2019
result = cell2mat(arrayfun(@(y)randperm(x)+(y-1)*x,y,'uni',false));

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Accepted Answer

James Tursa
James Tursa on 26 Aug 2019
One way:
>> result = cell2mat(arrayfun(@(y)x*y-x+1:x*y,y,'uni',false))
result =
1 2 3 7 8 9 13 14 15 10 11 12 4 5 6

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James Tursa
James Tursa on 26 Aug 2019
Do you also know x? And using result and x want to get y?
Josué Ortega
Josué Ortega on 26 Aug 2019
got it, apologies for the silly question

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