how to insert 1 in place of inf in a given array

given array :

Inf 4 2 2 4 Inf

i want my final output satisfy two conditions:

1. insert value 1 wherever Inf is encountered

2.insert value 1 wherever 2 or any number is encountered multiple times consequetively.

final output : 1 0 1 0 0 1

Edit: Thanks a lot,that worked like hot knife on butter :)

i've got another issue:I want to append 1 to start of every array

Ex-: a= [0 1 0 01]

my desired output= [1 0 1 0 0 1]

Answer 1

[Rik]

You can use the diff function and isinf to make this array.

final= [false diff(array)==0] | isinf(array) ;

[madhan ravi]

+1, and to match the final output :

flip(final)

edit: Stephen's comment is accurate. Thank you!

[Stephen23]

To match the output shown in the question just move the false:

final = [diff(array)==0,false] | isinf(array);

[anshuman mishra]

Thanks a lot,that worked like hot knife on butter :)

i've got another issue:I want to append 1 to start of every array

Ex-: a= [0 1 0 01]

my desired output= [1 0 1 0 0 1]

[Rik]

Like this?

[1 a]

[anshuman mishra]

thank you . one more help : how to count no. of 1s in the final array ?

[Rik]

The sum function can be used as a shorthand.

[Stephen23]

https://www.mathworks.com/help/matlab/ref/nnz.html