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could anyone help me to solve the issue with respect to the code

Asked by jaah navi on 18 Jun 2019
Latest activity Answered by Stephen Cobeldick on 18 Jun 2019
code:
A=1:7
B=length(A)
idx=randperm(B,1)
disp(idx)
the above code run one time and it displays idx value.
Could anyone help me to run the above code 5 times and for each time idx value should needs to be different.

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3 Answers

Answer by James Tursa
on 18 Jun 2019

The syntax of a for-loop is:
for k=1:5
% your code here
end

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code:
for k=1:5
A=1:7;
B=length(A);
idx=randperm(B,1);
disp(idx)
end
when i run the code it gives the same idx for some run.
what i actually need is it should be different for each run.

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Answer by Soumya Sinha on 18 Jun 2019

I assume that for this case, since you only want idx value to change and not the values of A or B
A = 1:7;
B=length(A);
for i = 1:5
idx = randperm(B,1);
disp(idx);
end

  2 Comments

ok.But the idx remains the same for more than one run when i run the code
idx = 1
idx = 1
idx = 1
idx = 7
idx = 4
What i actually need is idx should be different for each run.But with respect to the above result idx remains the same for three run .Could you please help me on this.
That's a perfectly normal behaviour, you might get same numbers on some occasions, when I tried I got all different numbers in some cases and I few repeating. Moreover, randomness wouldn't ensure uniqueness in your answer.

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Answer by Stephen Cobeldick on 18 Jun 2019

"What i actually need is idx should be different for each run"
The easiest way is to define them before the loop, e.g.:
A = 1:7
N = numel(A)
V = randperm(B,N)
for k = 1:N
A(k)
V(k)
end

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