1D Heat equation using an implicit method
Show older comments
hi guys,
so i made this program to solve the 1D heat equation with an implicit method.
i have a bar of length l=1
the boundaries conditions are T(0)=0 and T(l)=0
and the initial conditions are 1 if l/4<x<3*l/4 and 0 else.
i plot my solution but the the limits on the graph bother me because with an explicit method i have a better shape for the same problem.
if someone can help me solve the problem
clear, clc, close all
%% parametres
Nx = 40;
Nt = 1000;
dx = 1/(Nx-1);
c = 5;
l=1;
cfl = (2*c)/(2*c+1);
dt = cfl*(dx^2)/(2*c);
alpha = c*dt/dx^2;
beta = (1+2*alpha);
x = 0:dx:l;
%% construction de la matrice A
A = full(spdiags(ones(Nx,1)*[-alpha,beta,-alpha],[-1,0,1],Nx,Nx));
%% construction de la matrice b
b = ones(Nx,1);
b(1:Nx/4,1)=0; % initial conditions
b(3*Nx/4:Nx,1)=0; % initial conditions
%% %% %% %%t
time = 0;
for t = 0:dt:Nt
T = linsolve(A,b);
T(1) = 0; % boundary conditions
T(Nx) = 1; % boundary conditions
b = T;
time = time+dt;
figure(1), clf % Solution plot
plot(x,T);
xlabel('x [m]')
ylabel('Temperature [^oC]')
ylim([0 3])
drawnow
end
1 Comment
Youssef Benmoussa
on 12 Apr 2020
bonjour est ce que tu peut m'envoyer le code pour l'implicite ?
Answers (0)
Categories
Find more on Mathematics in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!