If/while loop to break or continue

Hello. I have setup a simple data set which illustrates the idea of my code. I have trouble setting up the loop to break/continue the current code. The comments explain the purpose of the code. Don't pay much attention to written for loop etc. its just showing its position in the code.

z = [1; 2; 5; 3; 4; 5]
x = [1 2 1 3 4; 3 2 1 2 1; 1 1 2 3 4;1 2 1 3 4; 3 2 1 2 1; 1 1 2 3 4]
limit = 2;

%%We want to compare z to each coloum of x. If value of z exceeds 5, then compared
%%value of x should be excluded. Which mean we only store compared values
%%when z are below 5.

%%We want to do it with a loop which breaks (remove the compared values
%%above of z) and then continues throught rest of the values. We have an
%%idea that a if or while loop could work.


for L:length(z)
    if(x > limit)
        break/continue     
end

[Adam Danz]

We want to compare z to each coloum of x. If value of z exceeds 5, then compared value of x should be excluded.

What do you mean by 'excluded'? You can't remove the number from the matrix unless you convert the matrix to a cell array. You could replace the value with NaNs. Also, none of the values in z exceed 5.

We want to do it with a loop which breaks (remove the compared values above of z) and then continues throught rest of the values.

You want the code to break (stop execution) or remove the value and continue? It can't do both.

[jacob gandrup]

Thank for your quick response. Sorry for bad explanation.

I want the code to break if it reaches or exceeds a specific value like "5". The value could also be 4 for that matter. I don't want it to remove a value. Just to break and then continue for the rest.

[Luna]

%% We want to do it with a loop which breaks (remove the compared values
%%above of z) and then continues throught rest of the values

You say we want to remove here. If it is not removed what is the result for the above arrays and while your limit is 2?

You say "If value of z exceeds 5" you don't want to do a calculation, but you look for if x > limit in the code. I really don't get your question.

[Adam Danz]

Sorry, I still don't have a solid understanding of the goal. The break() function terminates execution of a for-loop. So it can't 'break' and 'continue' at the same time.

Perhaps it would be better to explain the main goal of what you're doing. Also how does the 'limit' variable come into play? Is that the threshold of z that should break the loop?