Using range in a vector

10 views (last 30 days)
ck poon
ck poon on 21 Mar 2019
Commented: madhan ravi on 21 Mar 2019
How do you use a loop/if statement to generate a range for vector A. Vector A can be changed by the user but the code should check if the components of the vectors are within -100 to 100
%vector A is defined as :
%A = [-10:0.5:10] ;
A = [1 2 101];
B =[]; % start with empty B
% check if the contents of A are in the range of -100 to 100
max = 100;
min = -100;
if (A>=min)|(A<=max)
for i=[1:length(A)]
% append cube of A(i) to B
B = [B A(i)*A(i)*A(i)];
end
%display B
disp(B);
%display that code is invalid
else
fprintf("Invalid - not within range")
end
  2 Comments
madhan ravi
madhan ravi on 21 Mar 2019
fprintf('Within Range %d\n',A(A>=Min&A<=Max))
fprintf('Not Within Range %d\n',A(~(A>=Min&A<=Max)))
I used if A(A>=min&A<=max)
and got 1 8 1030301
but somehow im suppossed not to cube the components not within the range
A>=Min & A<=Max % index it with A and raise it to the power of three

Sign in to comment.

Accepted Answer

Jos (10584)
Jos (10584) on 21 Mar 2019
I am a little confused by your problem, but here are my thoughts. You might want to use the function ANY, or its sibling ALL, or apply logical indexing
A = [1 2 101]
if any(A > 100)
disp('At least one element of A is larger than 100.') ;
end
B = nan(size(A))
tf = A <= 100 % use logical indexing
B(tf) = A(tf) .^ 3 % only calculate cube for elements of A <= 100, other elements are NaN

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!