Laplace inversion for fractional-order transfer functions
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Ehsan Khorsandnejad
on 11 Feb 2019
Answered: Patel Mounika
on 20 Feb 2019
I am using the FOMCON toolbox, which enables me to introduce transfer functions with a fractional order. However, when I want to use the laplace inversion function, it works for simple cases but not for a bit complicated equations. Can anyone help me with this?
Example 1: works
syms s
TF = 1/s^0.5;
ilaplace(TF)
ans =
1/(t^(1/2)*pi^(1/2))
Example 2: does not work (only works when a = integer)
syms s
a = 0.5
TF = 1/(5 + (3*(s^a + (1/2^a)))/(s^a + (1/6^a)));
ilaplace(TF)
answ =
ilaplace(1/(((3*2^(1/2))/2 + 3*s^(1/2))/(6^(1/2)/6 + s^(1/2)) + 5), s, t)
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Accepted Answer
Patel Mounika
on 20 Feb 2019
The ilaplace function of the symbolic engine currently does not implement an explicit expression for
ilaplace(1/(5 + (3*(s^a + (1/2^a)))/(s^a + (1/6^a)))) if a is not an integer .
The ilaplace function computes the analytic closed inverse Laplace form of a transfer function. It seems that mathematically a closed inverse Laplace form for 1/(5 + (3*(s^a + (1/2^a)))/(s^a + (1/6^a))) for general a cannot be found out, so ilaplace function will not simplify it further.
Nevertheless, there is a community submission at MathWorks File Exchange which numerically approximates an inverse Laplace transform for any function of "s". Following is the link of the same:
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