How does phasez work?
5 views (last 30 days)
Show older comments
Nathan Jessurun
on 10 Dec 2018
Answered: Miriam Guadalupe Cruz Jimenez
on 13 Aug 2019
I thought phasez simply plots the unwrapped version of a filter's angle. However, I get different plots for the following methods:
% Filter to add reverb to sample -- Requires DSP toolbox
% Use the impulse response from a reverb-y building as the time domain filter impulse repsonse
[timeFilter, Fs] = audioread('ChurchImpulseResponse-16-44p1-mono-5secs.wav');
% For an FIR filter, the time domain coefficients are the taps of the filter
h = freqz(timeFilter, [1 zeros(1, length(timeFilter))]);
[phi, w] = phasez(h);
plot(w, phi);
hold on;
plot(w, unwrap(angle(h)));
xlabel('frequency (rad/sample)');
ylabel('phase (radians)')
legend({'phasez', 'unwrap(angle)'});
What causes these two plots to behave quite differently for the produced filter? Note that for most filters I've tried, these plot operations are synonymous.
0 Comments
Accepted Answer
Miriam Guadalupe Cruz Jimenez
on 13 Aug 2019
Hi! Indeed 'phasez()' plots the unwrapped angle, but 'phasez()' acts on the coefficients of the filter and 'unwrap(angle())' acts on the frequency response of the filter. Thus, in your code you should employ 'timeFilter' as the argument in 'phasez()' and 'h' as the argument of 'unwrap(angle())'. Attached your sample code with this modification.
timeFilter = [1 2 3 4 5 6 7 8 9];
h = freqz(timeFilter, [1 zeros(1, length(timeFilter))]);
[phi, w] = phasez(timeFilter);
plot(w, phi);
hold on;
plot(w, unwrap(angle(h)),'o');
xlabel('frequency (rad/sample)');
ylabel('phase (radians)')
legend({'phasez', 'unwrap(angle)'});
0 Comments
More Answers (0)
See Also
Categories
Find more on Filter Design in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!