how to do bitxor operation of two 1*255 matrix
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h1 =1x255 logical
h3 = 1x255 logical
howto do bitxor of h1 and h3
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Answers (2)
Greg
on 30 Nov 2018
Edited: Greg
on 30 Nov 2018
result = h1 | h3;
Edit: this is logical (bit) or, not xor. As posted elsewhere, simply use the xor function.
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Jan
on 30 Nov 2018
The error message is clear: The array sizes are different. Here the variables h1 (logical) and c (double) are concerned. So why do you ask for "h1 =1x255 logical, h3 = 1x255 logical"?
James Tursa
on 30 Nov 2018
Edited: James Tursa
on 30 Nov 2018
It's not entirely clear to me what operation you really want, but if the elements of h1 and h2 represent "bits", then you could just do this:
result = (h1 ~= h2); % equivalent of xor between the elements of h1 and h2
If h1 and h2 don't have the same number of elements, then that is a different problem that you will need to fix before doing the xor operation.
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