how can i display an answer for all iteration?
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sharifah shuthairah syed abdullah
on 31 Oct 2018
Commented: madhan ravi
on 31 Oct 2018
i have this coding for quadratic assignment problem (assign facilities to location using flow and distant matrix)
i want to display all the answer that i get from 10 iteration
%%read data
clc
clear
%flow
f=[ 0 90 10 23 43 0 0 0 0 0 0 0
90 0 0 0 0 88 0 0 0 0 0 0
10 0 0 0 0 0 26 16 0 0 0 0
23 0 0 0 0 0 0 0 0 0 0 0
43 0 0 0 0 0 0 0 0 0 0 0
0 88 0 0 0 0 0 0 1 0 0 0
0 0 26 0 0 0 0 0 0 0 0 0
0 0 16 0 0 0 0 0 0 96 0 0
0 0 0 0 0 1 0 0 0 0 29 0
0 0 0 0 0 0 0 96 0 0 0 37
0 0 0 0 0 0 0 0 29 0 0 0
0 0 0 0 0 0 0 0 0 37 0 0];
%distance
d=[ 0 36 54 26 59 72 9 34 79 17 46 95
36 0 73 35 90 58 30 78 35 44 79 36
54 73 0 21 10 97 58 66 69 61 54 63
26 35 21 0 93 12 46 40 37 48 68 85
59 90 10 93 0 64 5 29 76 16 5 76
72 58 97 12 64 0 96 55 38 54 0 34
9 30 58 46 5 96 0 83 35 11 56 37
34 78 66 40 29 55 83 0 44 12 15 80
79 35 69 37 76 38 35 44 0 64 39 33
17 44 61 48 16 54 11 12 64 0 70 86
46 79 54 68 5 0 56 15 39 70 0 18
95 36 63 85 76 34 37 80 33 86 18 0];
[r,c]=size(f);
max_i= r;
max_j =r;
max_k= r;
max_q= r;
MaxIt=10;
for no=1:MaxIt
ID=randperm(r); %PERMUTATION r NOMBOR ..r = 3, 1 2 3, 1 3 2...
x=zeros(r,r);
n=length(ID);
x1=ID;
for i=1:n
for j=1:r
x(j,x1(j))=1;
B(i).mat=x; % used to keep the memory when 0,1 permutation in (i),for BINARY RELATION
end
x=zeros(r,r);
end
z=0;xa=B(no).mat;
for i=1:max_i
for j=1:max_j
for k=1:max_k
for q=1:max_q
z= z+ f(i,k).*d(j,q).*xa(i,j).*xa(k,q); %find the min value of the assignment
end
end
end
end
no;
F(no,:)=[no z]; %STOR ALL VALUE Z 1...UNTIL MaxIt IN MATRIX F
end
%end
zmin=min(F(:,2));
ii=find(F(:,2)==zmin) ;
x_initial = B(ii).mat;
% xbin= B(ii).mat % xbin = initial value for facility location for minimun z
z_minimum = zmin
Iter_zvalue = F % matrix F has no of iteration..col 1 dan z
Iter_MaxIt = ID
% disp(ID)
i want to make it display the iteration as example below, but i didnt know how to do it
exp:
Iter_MaxIt 1=
11 4 7 5 12 3 9 1 2 8 6 10
F 1 =
31868
Iter_MaxIt 2=
11 4 7 5 12 3 9 1 2 8 6 10
F 2 =
31868
0 Comments
Accepted Answer
madhan ravi
on 31 Oct 2018
Apply condition inside loop as such
if Maxit
disp(yourvalues) which you want to display
end
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