Detect a jump in datetime - series
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Jeroen Vermond
on 14 Aug 2018
Commented: Jeroen Vermond
on 14 Aug 2018
Hi!
I have imported a table, including timestamp values. The string array, called t, has dimensions 8602x1. Around an index of 8000 there is a jump in time, see the following close up of the array:
"10.08.2018 11:37:08"
"10.08.2018 11:37:09"
"10.08.2018 11:37:10"
"10.08.2018 11:37:11"
"10.08.2018 11:37:14"
"10.08.2018 11:37:15"
"10.08.2018 12:12:01"
"10.08.2018 12:12:02"
"10.08.2018 12:12:03"
"10.08.2018 12:12:04"
I was looking in to the datetime function and I thought this could be useful to calculate the time difference between adjacent values. So I did the following:
t2 = datetime(t,'InputFormat','dd.MM.yyyy hh:mm:ss');
dt = diff(t2);
This works fine, except when time becomes larger than 12:00:00, in that case dt becomes negative. For the following values dt becomes -11:25:14:
"10.08.2018 11:37:15"
"10.08.2018 12:12:01"
I was wondering how to configure my script so it takes into account the 24h of a day. The final goal is to know at which index of the series a jump in time larger than for example 3s occurs. In my imported data a day starts (in this case 10:08:2018) at midnight, 00:00:00. Maybe someone knows how to achieve my goal?
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Accepted Answer
Adam Danz
on 14 Aug 2018
This just happened to me the other day.
Capitalize your 'hh'. It should be
= datetime(t,'InputFormat','dd.MM.yyyy HH:mm:ss');
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