Symbolic Substitution(subs) is not working , why?
    6 views (last 30 days)
  
       Show older comments
    
    Mirroyal Ismayilov
 on 27 Jul 2018
  
    
    
    
    
    Commented: Walter Roberson
      
      
 on 1 Aug 2018
            T(t) =
(25*diff(r1(t), t)^2)/12 + (25*diff(r2(t), t)^2)/8 + (25*cos(r1(t))^2*diff(r1(t), t)^2)/4 + (25*sin(r1(t))^2*diff(r1(t), t)^2)/4 + (3*(5*cos(r1(t))*diff(r1(t), t) + (5*cos(r2(t))*diff(r2(t), t))/2)^2)/2 + (3*(5*sin(r1(t))*diff(r1(t), t) + (5*sin(r2(t))*diff(r2(t), t))/2)^2)/2
T is gained from somewhere which is long story but it works perfectly fine. My code is following:
syms T r1(t) k1
subs(T,r1,k1);
P1=diff(T,k1);
Because I can't differentiate in terms of symbolic function, I wanted to replace r1 with k1, but it doesn't replace and subs function gives back these:
ans(t) =
(25*diff(r2(t), t)^2)/8 + (75*cos(r2(t))^2*diff(r2(t), t)^2)/8 + (75*sin(r2(t))^2*diff(r2(t), t)^2)/8
Somehow r1(t)'s are disappeared but couldn't been replaced with k1. Because there is not k1 in substituted function,differentiation(diff) gives back just 0(zero) which is normal.
Can someone explain me the situation please?
0 Comments
Accepted Answer
  Walter Roberson
      
      
 on 27 Jul 2018
        No, the substitution is working. But you have diff(r1(t),t) and when you replace r1(t) with k1, that becomes diff(k1, t) and since k1 is independent of t, the diff() becomes 0.
2 Comments
  Walter Roberson
      
      
 on 1 Aug 2018
				But what I recommend is that you look at the first example in odeFunction() to see how to convert equations with derivatives into systems of equations.
More Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
