how to find maximum distance from centroid to border of binary image

if true
  % code
end
for ii=1:size(bord2,1)
  for jj=1:size(bord2,2)
      pixel(ii,jj)=bord2(ii,jj);
      if(pixel(ii,jj)==1) 
       X = [xc yc;ii jj];
           r1(c) = pdist(X,'euclidean');

             c=c+1;         
        end   
    end
end

Answer 1

[KSSV]

I = imread('peppers.png') ;
[nx,ny,d] = size(I) ;

C = round([ny nx]/2) ;

imshow(I)
hold on
plot(C(1),C(2),'*r')

R = [1 1 ; 1 nx ; ny nx ; ny 1] ;  % four corners of the image 
d = sqrt((C(1)-R(:,1)).^2+(C(2)-R(:,2)).^2) ;

[sreerag kanhangad]

 actually i need to find out this distance(ie,the maximum distance between centroid and the white pixel)

[sreerag kanhangad]

thank you so much for your quick response

[KSSV]

That's more easy....get the locations of white pixels and use distance formula.

[KSSV]

YOu need not to run a loop..get pixel values at once using:

[y,x] = find(I) ;

Now find the distance between (x,y) and your center C. Pick the maximum of it.

[sreerag kanhangad]

if true
  % code
end
%bord2 is bw image,[xc,yc]-centroid
[xd,yd]=find(bord2);
X = [xc yc;xd yd];
dnew=pdist(X,'euclidean');
dnew=max(dnew);

please check out this

[KSSV]

You got your answer?

Answer 2

[sreerag kanhangad]

yeah at last i got the output..misplaced jj and ii.. [y,x] = find(I) tysm for this idea