My Program Is Ignoring my ELSE statement...How To Fix...Projectile Motion
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Taylor McMillan
on 31 May 2018
Answered: Walter Roberson
on 31 May 2018
I AM WANTING TO STOP PLOTTING ONCE Y < 0.
%{
This function was created by Taylor McMillan.
PURPOSE: Model simple projectile motion. Introduce students to Matlab.
ENTER THE FOLLOWING INTO THE COMMAND WINDOW:
ProjectileMotion(0.1, 0, 0, 50, pi/4, 30)
%}
%%START PROGRAM %%
function ProjectileMotion(time_step, xic, yic, vic, angic, max_time)
%%Create A Time Series %%
h = time_step;
N = max_time/h;
t = 0:h:max_time - h;
%%Initial Conditions / Parameters %%
x(1) = xic; % Initial x-position (meters)
y(1) = yic; % Initial y-position (meters)
v(1) = vic; % Initial speed (meters/second)
ang(1) = angic; % Initial launch angle (radians)
g = 9.81; % Acceleration due to gravity (meters/second/second)
%%Projectile Equations %%
if y >=0 && x >= 0
x = x(1) + v(1)*cos(ang(1))*t;
y = y(1) + v(1)*sin(ang(1))*t - 0.5*g*t.^2;
%%Plot The Motion %%
else
figure();
plot(x, y)
xlabel('x - position (m)', 'FontSize', 20)
ylabel('y - position (m)', 'FontSize', 20)
title('Trajectory', 'FontSize', 26)
end
END PROGRAM %%
end
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Accepted Answer
Walter Roberson
on 31 May 2018
Your initial x and y are 0 . 0 >=0 && 0 >= 0 so the code in the body if the "if" will be executed, and the "else" will not be executed. And then you get to the end of the function and return. You do not have a loop.
Your plot() assumes that x and y are vectors, consistent with you having initialized x(1) and y(1). But the code y >=0 && x >= 0 will fail as soon as y becomes a vector, because you cannot use && with vector values. You could try switching to & instead of && but remember that y >=0 & x >= 0 means the same as all(y >=0 & x >= 0)
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