Creating a random permutation that always start with a specific value

Dear all,

I want to create a vector of the size ten that starts with a the value one and the rest must be random. Therefore I wanted to do the following: N = [1 randperm(9)]. However, randperm only returns the values between 1 and 9 in such a case. Is there anyone who knows how this works or knows another function that could help me with my problem.

Kind regards, Thomas

Answer 1

[Birdman]

It sounds like randi function can help you. First argument specifies the interval that integer values will be generated. Second and third argument specifies the number of row and column respectively.

 N=[1 randi([2 9],1,8]

[Thomas Beerten]

Thanks for your answer. The problem with the answer is that it creates a vector that contains the same numbers since it creates random numbers. I wanted to use randperm such that each number is present only once in the vector. Such that you get a vector that looks the following: [1 2 3 4 5 7 6 8 9 10]. Do you may know if that is possible with the function randi?

Regards

[Birdman]

No that is not possible with randi. You may use randsample as follows to uniquely create numbers:

 randsample(1:10,10)

But the order will be random.

Answer 2

[Torsten]

N=[1 1+randperm(9)];

Best wishes

Torsten.