Help with 3D-plotting?
    5 views (last 30 days)
  
       Show older comments
    
    Lewis Hancox
 on 14 Mar 2018
  
    
    
    
    
    Commented: Star Strider
      
      
 on 14 Mar 2018
            So I have made this code that creates the shape I desire, but the top is open, and I want it to flat on the top. Any help would be appreciated. Thanks
if true
  % code
end
%Constants
A=7/4;
L=1;
R=1;
%Solve for u_2
syms u 
u_2=vpasolve(u*(-A-log(u)+u^2+3*u^4/4)*(1+u^2)^(-2)== L/R, u)
%x(u_2)=R rearranges to get C=...,
C=R*u_2/(1+u_2^2)^2
syms u
u_1=vpasolve(-log(u)+u^2+3*u^4/4 == A, u)
x_1=(C*(1+u_1^2)^2)/u_1
v= linspace (u_1,u_2);
  X= C*((1+v.^2).^2)./v;
  Y= L-C*(-A-log(v)+v.^2+(3*v.^4)/4);
  plot(X,Y)
 figure(1)
figure(2)  
u1 = double(u_1)
u2 = double(u_2)
syms r v
colormap(bone)
x=fsurf(cos(r)*C*((1+v.^2).^2)./v, sin(r)*C*((1+v.^2).^2)./v,(L-C*(-A-log(v)+v.^2+(3*v.^4)/4)),[0,2*pi u1, u2])
title('R=1 L=1')
0 Comments
Accepted Answer
  Star Strider
      
      
 on 14 Mar 2018
        Tweak figure(2) by adding a patch call:
figure(2)  
u1 = double(u_1)
u2 = double(u_2)
syms r v
colormap(bone)
x=fsurf(cos(r)*C*((1+v.^2).^2)./v, sin(r)*C*((1+v.^2).^2)./v,(L-C*(-A-log(v)+v.^2+(3*v.^4)/4)),[0,2*pi u1, u2])
hold on
rv = linspace(0,2*pi);
Radius = 0.35;
patch(Radius*cos(rv), Radius*sin(rv), ones(size(rv)), 'r')              % <— ADD THIS ‘patch’ CALL, REFINE ‘Radius’
hold off
title('R=1 L=1')
I don’t know how you define the value for the radius of the top, so I guessed at one that sort of works. Tweak that, change the colour to something you want, and it should work. See the documentation for patch to tweak its properties.
2 Comments
  Star Strider
      
      
 on 14 Mar 2018
				As always, my pleasure!
I’m not sure what to advise with respect to the colormap. That you’re using symbolic calculations and fplot makes that something of a challenge. Experiment using the last row of the colormap for the patch object colour. It could work!
More Answers (2)
  Lewis Hancox
 on 14 Mar 2018
        1 Comment
  Star Strider
      
      
 on 14 Mar 2018
				Good!
It likely would have been best for me to gave included that option, specifying a multiplier. It didn’t seem necessary originally.
See Also
Categories
				Find more on White in Help Center and File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!