i want to compute a cdf for t distribution

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i want to compute a cdf for t distribution from a to b , i wrote this code but it didn't run
for i=1:50
fa(i)=cdf('t', 'mu' =-2, 'sigma'= 4 , 'nu'= 6 , astar(i))
fb(i)=cdf('t', 'mu' =-2, 'sigma'= 4 , 'nu'= 6, bstar(i))
end
astar and bstar are points of the integral
sorry for a weak my language

Accepted Answer

Star Strider
Star Strider on 1 Mar 2018
You are not calling cdf correctly. Also the functions are vectorised, so you do not need the loops.
Try this:
fa = cdf('T', nu, astar);
fb = cdf('T', nu, bstar);
It is probably best to use the tcdf (link) function instead, since cdf appears to be deprecated in a future release of MATLAB.
  2 Comments
elham kreem
elham kreem on 1 Mar 2018
thanks for you , your answer for stander dist. and i apply it as : fa = cdf('T', 'nu', 6, astar) the result is : fa =
1.0000 1.0000
but if i want cdf for non stander distribution for t, I apply this code
fa=cdf('T', 'mu' ,-2, 'sigma', 4 , 'nu', 6 , astar)
but the result is :
fa =
NaN NaN
Star Strider
Star Strider on 1 Mar 2018
My pleasure.
In the t-distribution, ‘nu’ is calculated as described in Compute Student's t cdf (link). You use the mean (‘mu’), standard deviation (‘sigma’) and number of observations (‘n’) to calculate it. There is only one parameter.
If you use my code, you get the correct result:
astar = linspace(1E-5, 2, 5);
nu = 6;
fa = cdf('T', nu, astar)
I again urge you to use the tcdf function (that I linked to in my Answer), instead of cdf.

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