How to find the two nearest values related to a constant

Hello to all,
I've to find what are the two values and related indices respect to a constant.
I mean as example; I've a vector and a constant like follow:
a=[1250 2320 3520 4650 5550 6760];
b= 3700;
Therefore I would receive the values 3520 and 4650 and the equivalent indices 3 e 4.
Best regards and thanks in advance.

 Accepted Answer

a=[1250 2320 3520 4650 5550 6760];
b= 3700;
% this will work even if 'a' is in random order
d=sort(abs(b-a));
lowest=find(abs(b-a)==d(1))
sec_lowest=find(abs(b-a)==d(2))

3 Comments

Thank you Thomas for your troubleshooting.
It works fine because sorts the data also if there are negative numbers and as you sad also with random numbers.
Best regards.
This doesnt work if d(1) and d(2) are equal, meaning b sits exactly halfway between two values in a. An easy way to solve this is with an if statement.
d=sort(abs(b-a));
if (d(1) == d(2))
vals = find(abs(b-a)==d(1))
lowest = vals(1)
second_lowest = vals(2)
else
lowest=find(abs(b-a)==d(1))
sec_lowest=find(abs(b-a)==d(2))
end
Tomas, instead of using find, you can use the second output of sort, which is the index for the sorting.

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More Answers (2)

a=[1250 2320 3520 4650 5550 6760];
b= 3700;
[~,e] = histc(b,a)
out = [a(e+(0:1)) ; e+(0:1)]
firstIndex = find(a<b, 1, 'last')
nextIndex = firstIndex + 1

2 Comments

Only works if a is consistently increasing. If a= e.g. [0, -1, -2, -3] and b = -1.4 then firstIndex = find(a<b, 1, 'last') returns -2 and nextIndex returns -3 which is not correct. You can't simply check absoloute values in case the slope reverses at some point.
Yes, you're right. A much better answer would have been:
a=[1250 2320 3520 4650 5550 6760]
b= 3700
differences = abs(a-b)
[minDiff, indexOfMinDiff] = min(differences);
closestValue = a(indexOfMinDiff);
message = sprintf('The value in "a" closest to "b" is %d', closestValue);
uiwait(helpdlg(message));

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on 11 May 2012

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on 5 Aug 2018

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