Strfind to contain complex pattern
1 view (last 30 days)
Show older comments
I have created the following program to search for sentences. I want to include those that only begin with vowels.
a = 'John played volleyball. I love Anna. Are you there?'
b = strfind(a,'.')
y{1} = a(1:b(1))
for i=2:length(b)
y{i} = a(b(i-1)+1:b(i))
end
y{i+1} = a((b(i)+1):end)
0 Comments
Accepted Answer
Cedric
on 3 Jan 2018
Edited: Cedric
on 3 Jan 2018
Here is an approach:
str = 'John played volleyball. I love Anna. Are you there?' ;
buffer = strtrim( strsplit( str, {'.', '?', '!'} )) ;
for k = numel( buffer ) : -1 : 1
if isempty( buffer{k} ) || ~any( upper(buffer{k}(1)) == 'AEIOUY' )
buffer(k) = [] ;
end
end
Running this, you get:
>> buffer
buffer =
1×2 cell array
{'I love Anna'} {'Are you there'}
If you don't understand, evaluate the following expression independently, and analyze their output:
strsplit( 'John played volleyball. I love Anna. Are you there?', {'.', '?', '!'} )
buffer = strtrim( strsplit( 'John played volleyball. I love Anna. Are you there?', {'.', '?', '!'} ))
upper(buffer{1}(1))
upper(buffer{1}(1)) == 'AEIOUY'
any( upper(buffer{1}(1)) == 'AEIOUY' )
upper(buffer{2}(1))
upper(buffer{2}(1)) == 'AEIOUY'
any( upper(buffer{2}(1)) == 'AEIOUY' )
PS: this could also be done using regular expressions, but more classic approaches (like the above) should be understood first.
PS2: your first attempt is good actually. You try to implement STRSPLIT and it works to some extent; it was good training, but it would have to be extended to support multiple delimiters. If you run the expressions above, you will realize that STRSPLIT does the split (outputs a cell array). You may have to use another approach if you need to keep the delimiters (.?!) though (see PS3). STRSPLIT leaves the leading and trailing spaces, which is a problem if you want to test the first character, hence the call to STRTRIM. The output of STRTRIM is a cell array of "clean" sentences. The loop removes all entries that don't start with a vowel. It needs to go backwards from the end of the array, otherwise indexing is messed up.
PS3: If you need to keep the punctuation, replace the call to STRSPLIT with a call to REGEXP, as follows:
buffer = strtrim( regexp( str, '.*?[\.!\?]', 'match' )) ;
0 Comments
More Answers (0)
See Also
Categories
Find more on Characters and Strings in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!