How can I simulate OFDM with Rayleigh fading by using Communications System Toolbox?

69 views (last 30 days)
I would like to adapt the example code in the following link such that the AWGN channel is preceded by a Rayleigh fading channel.
https://www.mathworks.com/help/comm/gs/qpsk-and-ofdm-with-matlab-system-objects-1.html
My code gives a bit-error rate of approximately 0.5, regardless of the signal-to-noise ratio. Could you please tell me what I am doing wrong?
M = 4; % Modulation alphabet
k = log2(M); % Bits/symbol
numSC = 128; % Number of OFDM subcarriers
cpLen = 32; % OFDM cyclic prefix length
maxBitErrors = 1e2; % Maximum number of bit errors
maxNumBits = 1e7; % Maximum number of bits transmitted
qpskMod = comm.QPSKModulator('BitInput',true);
qpskDemod = comm.QPSKDemodulator('BitOutput',true);
ofdmMod = comm.OFDMModulator('FFTLength',numSC,'CyclicPrefixLength',cpLen);
ofdmDemod = comm.OFDMDemodulator('FFTLength',numSC,'CyclicPrefixLength',cpLen);
rayleighChannel = comm.RayleighChannel;
awgnChannel = comm.AWGNChannel('NoiseMethod','Variance', 'VarianceSource','Input port');
errorRate = comm.ErrorRate('ResetInputPort',true);
ofdmDims = info(ofdmMod);
numDC = ofdmDims.DataInputSize(1);
frameSize = [k*numDC 1];
EbNoVec = (0:20)';
snrVec = EbNoVec + 10*log10(k) + 10*log10(numDC/numSC);
berVec = zeros(length(EbNoVec),3);
errorStats = zeros(1,3);
for m = 1:length(EbNoVec)
snr = snrVec(m);
while errorStats(2) <= maxBitErrors && errorStats(3) <= maxNumBits
dataIn = randi([0,1],frameSize); % Generate binary data
qpskTx = qpskMod(dataIn); % Apply QPSK modulation
txSig = ofdmMod(qpskTx); % Apply OFDM modulation
fadedSig = rayleighChannel(txSig);
powerDB = 10*log10(var(fadedSig)); % Calculate Tx signal power
noiseVar = 10.^(0.1*(powerDB-snr)); % Calculate the noise variance
rxSig = awgnChannel(fadedSig,noiseVar); % Pass the signal through a noisy channel
qpskRx = ofdmDemod(rxSig); % Apply OFDM demodulation
dataOut = qpskDemod(qpskRx); % Apply QPSK demodulation
errorStats = errorRate(dataIn,dataOut,0); % Collect error statistics
end
berVec(m,:) = errorStats; % Save BER data
errorStats = errorRate(dataIn,dataOut,1); % Reset the error rate calculator
end
berTheory = berawgn(EbNoVec,'psk',M,'nondiff');
berTheory_2 = berfading(EbNoVec,'psk',M,1);
figure
semilogy(EbNoVec,berVec(:,1),'*')
hold on
semilogy(EbNoVec,berTheory_2)
legend('Simulation','Theory','Location','Best')
xlabel('Eb/No (dB)')
ylabel('Bit Error Rate')
grid on
hold off

Answers (6)

Ahmed Aladi
Ahmed Aladi on 24 Sep 2020
clear all;
M = 4; % Modulation alphabet
k = log2(M); % Bits/symbol
numSC = 128; % Number of OFDM subcarriers
cpLen = 32; % OFDM cyclic prefix length
maxBitErrors = 1e3; % Maximum number of bit errors
maxNumBits = 1e7; % Maximum number of bits transmitted
qpskMod = comm.QPSKModulator('BitInput',true);
qpskDemod = comm.QPSKDemodulator('BitOutput',true);
ofdmMod = comm.OFDMModulator('FFTLength',numSC,'CyclicPrefixLength',cpLen);
ofdmDemod = comm.OFDMDemodulator('FFTLength',numSC,'CyclicPrefixLength',cpLen);
awgnChannel = comm.AWGNChannel('NoiseMethod','Variance', 'VarianceSource','Input port');
errorRate = comm.ErrorRate('ResetInputPort',true);
ofdmDims = info(ofdmMod);
numDC = ofdmDims.DataInputSize(1);
frameSize = [k*numDC 1];
EbNoVec = (0:20)';
snrVec = EbNoVec + 10*log10(k) + 10*log10(numDC/numSC);
berVec = zeros(length(EbNoVec),3);
errorStats = zeros(1,3);
for m = 1:length(EbNoVec)
snr = snrVec(m);
while errorStats(2) <= maxBitErrors && errorStats(3) <= maxNumBits
dataIn = randi([0,1],frameSize); % Generate binary data
qpskTx = qpskMod(dataIn); % Apply QPSK modulation
txSig = ofdmMod(qpskTx); % Apply OFDM modulation
%fadedSig = rayleighChannel(txSig);
%% Rayleigh Fading Channel
taps=3; %number of channel taps
h = [randn(1,taps)+j*randn(1,taps) zeros(1,size(txSig,1)-taps)].' ; % generate channel taps and pad with zeros
h_t = toeplitz(h); % channel matrix
fadedSig=h_t*txSig; % Apply Rayleigh fading
powerDB = 10*log10(var(fadedSig)); % Calculate Tx signal power
noiseVar = 10.^(0.1*(powerDB-snr)); % Calculate the noise variance
rxSig = awgnChannel(fadedSig,noiseVar); % Pass the signal through a noisy channel
rxSig_eq = inv(h_t'*h_t)*(h_t')*rxSig; % zero forcing equalization
% Apply OFDM demodulation
qpskRx = ofdmDemod(rxSig_eq);
dataOut = qpskDemod(qpskRx); % Apply QPSK demodulation
errorStats = errorRate(dataIn,dataOut,0); % Collect error statistics
end
berVec(m,:) = errorStats; % Save BER data
errorStats = errorRate(dataIn,dataOut,1); % Reset the error rate calculator
end
berTheory = berawgn(EbNoVec,'psk',M,'nondiff');
berTheory_2 = berfading(EbNoVec,'psk',M,1);
figure
semilogy(EbNoVec,berVec(:,1),'*')
hold on
semilogy(EbNoVec,berTheory_2)
legend('Simulation','Theory','Location','Best')
xlabel('Eb/No (dB)')
ylabel('Bit Error Rate')
grid on
hold off
  6 Comments

Sign in to comment.


N/A
N/A on 9 Sep 2020
I think the problem is when you generate the rayleigh channel, try to add some inputs such as the sampling time/frequency, the maximum doppler shift and you can add also the delays and there pdp,
Here is an exampe of how I simulate an EVA channel :
DS = 1e-9;
Tau = [0 30 150 310 370 710 1090 1730 2510]*DS;
Pdp = [0 -1.5 -1.4 -3.6 -0.6 -9.1 -7 -12 -16.9];
fd = 20/3.6*fc/c; % Maximum Doppler Shift
chan = rayleighchan(Ts, fd, Tau, Pdp);
with Ts being the sampling time,

N/A
N/A on 8 Jul 2019
Did you find the problem with your program ?

mustafa sami
mustafa sami on 15 Feb 2020
Did you find the problem with your program ?

Yasantha Samarawickrama
Yasantha Samarawickrama on 8 Sep 2020
I am encountering the same problem? Can you please share if you found the solution for this issue?

Yue Shang
Yue Shang on 5 Aug 2021
Some thoughts on the solution using comm.RayleighChannel
  1. The frequency-flat fading channel just applies a gain to each sample to the channel. The gain is the second output of the comm.RayleighChannel object's step method, i.e., pathGains. So the time-domain equalization can be done as rxSig_eq=rxSig./pathGains for ZF or rxSig_eq = rxSig.*conj(pathGains)./(abs(pathGains).^2+noiseVar) for MMSE.
  2. Set the MaximumDopplerShift property of comm.RayleighChannel to a larger number such as 0.1 for the channel to vary more quickly so you have the channel's "average" behavior in a shorter period of time. As a result, the maxBitErrors can be reduced for a shorter simulation.
  3. For this frequency-flat fading channel, the time-domain equation is simpler. For a frequency-selective channel with multipath (when PathDelays and AveragePathGains properties of comm.RayleighChannel are vectors), using a frequency-domain equalization after OFDM demodulation is usually simpler. You can refer to the Indoor MIMO-OFDM Communication Link using Ray Tracing example and in particular the helperIndoorRayTracingRxProcessing function in it for how this can be done.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!