Can you create a matrix using a for loop
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Is possible to create a matrix by just using for loops Thanks
2 Comments
chandrapal Singh
on 9 Dec 2017
what type of matrix? can you please provide more details regarding this query?
Stephen23
on 9 Dec 2017
"Is possible to create a matrix by just using for loops"
Yes.
Answers (2)
Amy
on 11 Dec 2017
0 votes
Look at the first example in the documentation for 'for': https://www.mathworks.com/help/matlab/ref/for.html
Lam Nguyen Van
on 10 Mar 2020
0 votes
Hi,
I want to creat matrices automatically with for loop in Matlab?
phi1=30; phi2=45; phi3=90;
After running the code I want to have a matric A with the following elements:
A=[sin(phi1) cos(phi1) sin(phi1)*cos(phi1);
sin(phi2) cos(phi2) sin(phi2)*cos(phi2);
sin(phi3) cos(phi3) sin(phi3)*cos(phi3);]
3 Comments
chandrapal Singh
on 10 Mar 2020
lengthy code for query
phi1=30; phi2=45; phi3=90;
rows= 3;
cols=3;
A= zeros(3);
row_num=1;
col_num =1;
for i = 1: 3
if row_num ==1
A(1,i)= sin(phi1);
col_num =col_num+1;
if col_num ==2
A(1,col_num)= cos(phi1);
col_num =col_num+1;
end
if col_num ==3
A(1,col_num)= sin(phi1)*cos(phi1);
col_num =col_num+1;
end
row_num=row_num+1;
end
col_num=1;
if row_num ==2
A(2,i)= sin(phi2);
col_num =col_num+1;
if col_num ==2
A(2,col_num)= cos(phi2);
col_num =col_num+1;
end
if col_num ==3
A(2,col_num)= sin(phi2)*cos(phi2);
col_num =col_num+1;
end
row_num=row_num+1;
end
col_num=1;
if row_num ==3
A(3,i)= sin(phi3);
col_num =col_num+1;
if col_num ==2
A(3,col_num)= cos(phi3);
col_num =col_num+1;
end
if col_num ==3
A(3,col_num)= sin(phi3)*cos(phi3);
col_num =col_num+1;
end
row_num=row_num+1;
end
end
Lam Nguyen Van
on 10 Mar 2020
Thanks!
I want to use
for i=1:3
for j=1:3
A(i,j)=...;
end
end
I want shorter code.
Lam Nguyen Van
on 11 Mar 2020
I did it. I used for loop and function.
phi=[30, 45, 90];
n=length(phi);
[e]=xuat_vecto(phi1);
A=zeros(n,3);
for i=1:n
[d]= xuat_vecto (phi(i));
A(i,:)=[d];
end
A
function [e]=xuat_vecto(alpha)
[a, b, c]=ham_luong_giac (alpha);
e=[a, b, c];
end
function [a1, a2, a3] = ham_luong_giac (phi)
a1=sin(phi);
a2=cos(phi);
a3=sin(phi)*cos(phi);
xuat= [a1, a2, a3];
end
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