how to make symbolic answer better looking ?

hello I used solve function to solve a an eqution how ever the answer is very long for exmaple here is the answer

   (R*R1*((R^4*U^2 + 2*R^3*R_C*U^2 - 2*R^3*R_C*U*V - 2*R^3*R_C1*U*V - 4*R1*R^3*V^2 - 4*R1*V_diode*R^3*V + R^2*R_C^2*U^2 - 2*R^2*R_C^2*U*V + R^2*R_C^2*V^2 - 4*R^2*R_C*R_C1*U*V + 2*R^2*R_C*R_C1*V^2 - 8*R1*R^2*R_C*V^2 - 8*R1*V_diode*R^2*R_C*V + R^2*R_C1^2*V^2 - 4*R1*R2*R^2*V^2 - 2*R*R_C^2*R_C1*U*V + 2*R*R_C^2*R_C1*V^2 - 4*R1*R*R_C^2*V^2 - 4*R1*V_diode*R*R_C^2*V + 2*R*R_C*R_C1^2*V^2 - 8*R1*R2*R*R_C*V^2 + R_C^2*R_C1^2*V^2 - 4*R1*R2*R_C^2*V^2)^(1/2) - R^2*U - R*R_C*U + R*R_C*V + R*R_C1*V + R_C*R_C1*V))/(2*(R1*R^2 + R1*R_C*R)*(R*V + R2*V + R*V_diode)) - (R*R_C*V - R*R_C*U - R^2*U + R*R_C1*V + R_C*R_C1*V)/((R + R_C)*(R*V + R2*V + R*V_diode))

as u can see the answer is very long , is there a wat to show the answer as a Fraction ?

Answer 1

[Star Strider]

First, see if the simplify command helps.

To get the numerator and denominator, use the numden function.

To get somewhat more understandable output, use the pretty function. (You cannot use this in code. It is for display only).