Converting Python to Matlab
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Spent a few hours on trying to figure out why the outputs are different, no luck. Python and Matlab are in a txt file along with their outputs.
Suggestions on what I should be looking at to resolve the issue?
2 Comments
Walter Roberson
on 24 Oct 2017
We do not have the data or NumPanels to test with.
Zach Dunagan
on 24 Oct 2017
Edited: Zach Dunagan
on 25 Oct 2017
Accepted Answer
More Answers (2)
Zach Dunagan
on 25 Oct 2017
Edited: Walter Roberson
on 25 Oct 2017
15 Comments
Walter Roberson
on 25 Oct 2017
For the special case of square matrices, often the easiest way is
M - diag(diag(M))
For other matrices,
tril(M,1) + triu(M,1)
Zach Dunagan
on 26 Oct 2017
Walter Roberson
on 26 Oct 2017
Just in case you have unsigned integers or the case where the existing value is so different from the new value that you have to worry about loss of precision:
Square matrix:
M(1:size(M,1)+1:end) = NewNumber;
Non-square matrix:
shorter = min(size(M,1),size(M,2));
lastidx = size(M,1)*(shorter-1)+shorter;
M(1:size(M,1)+1:lastidx) = NewNumber;
Zach Dunagan
on 26 Oct 2017
Walter Roberson
on 26 Oct 2017
M is the array whose diagonal is to be set. For example,
nSource(1:size(nSource,1)+1:end) = NewNumber;
if nSource is square.
Zach Dunagan
on 26 Oct 2017
Edited: Walter Roberson
on 26 Oct 2017
Zach Dunagan
on 26 Oct 2017
Edited: Walter Roberson
on 26 Oct 2017
Walter Roberson
on 26 Oct 2017
A[:numPanels,:numPanels]=nSource
would be
A(1:end-1, 1:end-1) = nSource;
I am not certain about
A[:numPanels,-1]=np.sum(nVortex,axis=1)
but I suspect
A(1:end-1, end) = sum(nVortex, 2);
Zach Dunagan
on 26 Oct 2017
Zach Dunagan
on 26 Oct 2017
Andrei Bobrov
on 26 Oct 2017
A(end, 1:end-1) = tSource(1, :) + tSource(end, :);
Zach Dunagan
on 27 Oct 2017
Zach Dunagan
on 28 Oct 2017
Edited: Walter Roberson
on 28 Oct 2017
Zach Dunagan
on 28 Oct 2017
Edited: Walter Roberson
on 28 Oct 2017
Zach Dunagan
on 28 Oct 2017
ASHOK KUMAR MEENA
on 18 Apr 2022
0 votes
def Lagrange(x, y, n, xx):
sum = 0
for i in range(0, n + 1):
product = y[i]
for j in range(0, n + 1):
if (i != j):
product = product * (xx - x[j]) / (x[i] - x[j])
sum += product
return sum
def Trapezoidal(h, n, f):
sum = f[0]
for i in range (1, n):
sum = sum + 2 * f[i]
sum = sum + f[n]
ans = h * sum / 2
return ans
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