How to change element in base 10 to base 2 in a matrix, with loops and while

Suppose i have a matrix called A,the elements ib base 10,how do i convert to base 2 .with conditions and loops.

[Geoff Hayes]

yuval - this sounds like homework. What have you tried so far?

[yuval ohayon]

 n=randi (6)
 A=randi(100,n,n)
 For (i=1:i < 100:i++)

Didnt know the 2nd base formula,it seems using sort or find func for reaching the element.the the formula to convert the element to 2nd base

[yuval ohayon]

Can i find some help?

[Jose Marques]

what are the coditions?

[John D'Errico]

What makes this not a doit4me? After all, it is trivial to use dec2bin, IF you just want to convert to base 2. Since you are not allowed to use dec2bin means it is homework. That you have apparently done nothing at all, this makes it a doit4me.

If you want help, then make an effort. How would you convert to base 2 if you were using pencil and paper? What, for example, would you do if you wanted to write the decimal number 27 in base 2? Once you understand the basic algorithm, it is easy to write code. But you need to make an effort on your homework.

[Walter Roberson]

In MATLAB,

   For (i=1:i < 100:i++)

would be written

for i = 1 : 99

However I do not see any connection between your question and any of the code you gave ?

[yuval ohayon]

Can figure it out .is their destination veriable that need to get the 2nd base number after i convert it? .the algorithem is a loop ,divide the indexed element in 2,with a loop .helpp

[Walter Roberson]

current_number = randi(32483209);   %create an input

last_bit = mod(current_number, 2);
current_number = (current_number - last_bit)/2;

[yuval ohayon]

function [  ] = dectobin( current_num)
binary_num=CHAR(a)
while (current_num~=0)
last_bit=mod(current_num,2);
current_num=(current_num-last_bit)/2;
binary_num=lastbit;

this is the function ,i need help to finish it and return to main program

[Walter Roberson]

What is a ?

I notice you are not recording the sequence of last_bit values.

I notice you are not returning any value from the function.

[yuval ohayon]

you are right, i need to return 1 variable, and i need recording the sequence i thought that's connect somehow to the char(a), its nonsense... but after i adding output variable, how do i record sequence of '1' '0' , AND HOW IN THE MAIN PROGRAM THE FUNC REPLACE FOR THE ALL MATRIX AND NT FOR SINGLE NUMBER

[Walter Roberson]

Generally speaking:

count = 0;
variable = [];
while true
  if I am not done yet
    count = count + 1;
    variable(count) = some value;
  else
    break;
  end
end

In your situation you will probably need to reverse the order of the variable afterwards

[yuval ohayon]

o.k i understood that i need define a matrix (veriable in the example) and the places of each element is indexed by the 'count' but how i store the last bit and adding the next one until i get a string like '1001001',say binnum=1001001 veriavle(count)=binnum; and

function [y] = dectobin(current_num)
binary_num=0
while (current_num~=0)
last_bit=mod(current_num,2); %is the function is right?what i have missing?
current_num=(current_num-last_bit)/2;
binary_num=lastbit;

[Walter Roberson]

variable(count) = lastbit;

Yes, mod(current_num,2) is fine to extract the last bit.

Answer 1

[Jose Marques]

A = magic(5) %generating a matrix 5x5
A = (A<10)   %suppose you want the elements in A < 10

[Jose Marques]